(2x^2+9)-(3x^2-7)=0

Solution for (2x^2+9)-(3x^2-7)=0 equation:

Simplifying
(2x2 + 9) + -1(3x2 + -7) = 0

Reorder the terms:
(9 + 2x2) + -1(3x2 + -7) = 0

Remove parenthesis around (9 + 2x2)
9 + 2x2 + -1(3x2 + -7) = 0

Reorder the terms:
9 + 2x2 + -1(-7 + 3x2) = 0
9 + 2x2 + (-7 * -1 + 3x2 * -1) = 0
9 + 2x2 + (7 + -3x2) = 0

Reorder the terms:
9 + 7 + 2x2 + -3x2 = 0

Combine like terms: 9 + 7 = 16
16 + 2x2 + -3x2 = 0

Combine like terms: 2x2 + -3x2 = -1x2
16 + -1x2 = 0

Solving
16 + -1x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + -1x2 = 0 + -16

Combine like terms: 16 + -16 = 0
0 + -1x2 = 0 + -16
-1x2 = 0 + -16

Combine like terms: 0 + -16 = -16
-1x2 = -16

Divide each side by '-1'.
x2 = 16

Simplifying
x2 = 16

Take the square root of each side:
x = {-4, 4}